Question

factorise : x²-under root 2x -4​

Answer 1

ANSWER:

x²+2√2x+2=0

\mathtt{x²+√2x+√2x+2 = 0}x²+√2x+√2x+2=0

\mathtt{x(x+√2)+√2(x+√2) = 0}x(x+√2)+√2(x+√2)=0

\mathtt{(x+√2)(x+√2) = 0}(x+√2)(x+√2)=0

\mathtt{(x+√2)= 0 \;\;\;or\;\;\;(x+√2)=0}(x+√2)=0or(x+√2)=0

\mathtt{x=-√2 \;\;\; or \;\;\;x=-√2}x=−√2orx=−√2

\mathtt{Hence, \; x=√2 \; \& \; x=√2 \; is \; the \; root \; of \; x²+2√2x+2=0}Hence,x=√2&x=√2istherootofx

Step-by-step explanation:

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