Question

factorise x²+x/4-1/8​

Answer 1

$x {}^{2} + \frac{x}{4} - \frac{1}{8} = 0\\ = > \frac{8x {}^{2} + 2x - 1}{8} = 0\\ = > 8x {}^{2} + 2x - 1 = 0 \\ = > 8x {}^{2} + 4x - 2x - 1 = 0 \\ = > 4x(2x + 1) - 1(2x + 1) = 0 \\ = > (4x - 1)(2x + 1)$

Answer 2

Hey mate here is your answer!!