Factorise
(x2 - x) (4x2 - 4x - 5) - 6
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Answered by
9
To see the structure, let's change the form slightly.
→ 4x² - 4x - 5 = 4(x² - x) - 5
Now there are common parts.
→ 4(x² - x)² - 5(x² - x) - 6
= {4(x² - x) + 3}{(x² - x) - 2}
= (4x² - 4x + 3)(x² - x - 2)
The final factorization is (4x² - 4x + 3)(x + 1)(x - 2).
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sorry for answering :) give the other guy brainliest thanks
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