Factorise x²-x+6 by splitting the middle term
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Answered by
1
Answer:
hey!
Step-by-step explanation:
x^2 -x -6
(now multiply the coefficient of the x^2 term and the constant)
(1*6=6)
now split x in such a way that we multiply the coefficients we get 6
x^2 +3x -2x -6=0
x( x+3) -2(x+3)=0
(x-2) (x+3)=0
now equate each term to 0
(x-2)=0
thus, x=2
(x+3)=0
thus, x=(-3)
thus... x= 2, (-3)
Answered by
2
Answer:
x²-x+6
x²+2x-3x+6
x(x+2) -3(x+2)
(x+2) (x-3)
x+2 = 0
x = -2
; x-3 = 0
x = 3
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