Question

factorise x²-xy-6y² explain me​

Answer 1

Answer:

Multiply the first and last terms then find its factor whose sum is at the middle term of the given the substitue to the middle term

x²+xy-6y²

[(x²)(-6y²) = -6x²y²]

Let the two terms are (-2xy) & (3xy)[(3xy)(-2xy) = -6x²y²]

[3xy-2xy = xy]

x²-2xy+3xy-6y²

(x²-2xy)+(3xy-6y²)

x(x-2y)+3y(x-2y)

Answer: (x+3y)(x-2y)

Step-by-step explanation:

hope it HELPS you

Answer 2

Answer:

x×x-xy-6y×y

Step-by-step explanation:

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