factorise x²-(y+z)² please helo to find the answer of this question
Answers
Answer:
Given that: x
2
+6x+8
=x
2
+4x+2x+8, (split middle term)
=(x
2
+4x)+(2x+8), (group pair of terms)
=x(x+4)+2(x+4), (factor each binomials)
=(x+4)(x+2), (factor out common factor (x+4)
Hence factors of x
2
+6x+8 are (x+4)(x+2)
Given : x²-(y+z)²
To Find : Factors
Solution:
x²-(y+z)²
Using identity
a² - b² = (a + b)(a - b)
a = x
b = ( y + z)
= (x + y + z)(x - (y + z))
= ( x + y + z)(x - y - z)
x²-(y+z)² = ( x + y + z)(x - y - z)
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