factorise x²–y²/100 by using appropriate properties
Answers
Answered by
5
Hii mate,
Just simple concept,
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Additional information:
- (a+ b)² = a²+2ab +b²
- (a-b)² = a²-2ab +b²
- a²+b² = (a+b)(a-b)
Answered by
0
Step-by-step explanation:
Hii mate,
Just simple concept,
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\begin{gathered}\bf \implies \: {x}^{2} - \frac{ {y}^{2} }{100} \\ \\ \bf \implies \: {x}^{2} - ( \frac{y}{10} ) ^{2} \\ \\ \bf \implies \: ( {x} + \frac{y}{10} ) ({x} + \frac{y}{10} ) \: \: \: \: \: \: \\ \\ \bf \: since \: \: {a}^{2} - {b}^{2} = (a + b)(a - b)\end{gathered}
⟹x
2
−
100
y
2
⟹x
2
−(
10
y
)
2
⟹(x+
10
y
)(x+
10
y
)
sincea
2
−b
2
=(a+b)(a−b)
________________________
________________________
Additional information:
(a+ b)² = a²+2ab +b²
(a-b)² = a²-2ab +b²
a²+b² = (a+b)(a-b)
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