Question

factorise : x³+1
please it's urgent
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Answer 1

Answer:

Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2) a 3 - b 3 = ( a - b ) ( a 2 + a b + b 2 ) where a=x and b=1 . Simplify. Multiply x x by 1 1 . One to any power is one.

Answer 2

=>x^3+1

=>x^3-1x^2+x+x^2-x+1

=>x^3-1x^2+1x+x^2-x+1

=>x^3-1.xx+1x+x^2-x+1

=>x(x^2-x+1)+x^2-x+1

=>x(x^2-x+1)+1(x^2-x+1)

=>(x+1)(x^2-x+1)