Math, asked by amitkamboj5556, 11 months ago

Factorise: x³-1³-10x²-53x-41

Answers

Answered by ashoktax80
0

Answer:

Step-by-step explanation:

X³ - 10x² - 53x - 42

= x³ + x² - 11x² - 11x - 42x - 42

= x²(x + 1) - 11x(x + 1) - 42(x + 1)

= (x + 1)(x² - 11x - 42)

= (x + 1)(x² - 14x +3x - 42)

= (x + 1){x(x - 14) + 3(x - 14) }

= (x + 1)(x + 3)(x - 14)

Hence, (x + 1), (x + 3) and (x - 14) are factors of x³ - 10x² - 53x - 42

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