Factorise: x³-1³-10x²-53x-41
Answers
Answered by
0
Answer:
Step-by-step explanation:
X³ - 10x² - 53x - 42
= x³ + x² - 11x² - 11x - 42x - 42
= x²(x + 1) - 11x(x + 1) - 42(x + 1)
= (x + 1)(x² - 11x - 42)
= (x + 1)(x² - 14x +3x - 42)
= (x + 1){x(x - 14) + 3(x - 14) }
= (x + 1)(x + 3)(x - 14)
Hence, (x + 1), (x + 3) and (x - 14) are factors of x³ - 10x² - 53x - 42
Similar questions