Question

Factorise: x3 +13 x2 + 32x + 20 using division method

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Answer 1

Answer:

hope it will helps you

Step-by-step explanation:

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Answer 2

Answer:

x3 + 13x2 + 32x + 20 = (x + 1)(x2 + 12x + 20) = (x + 1) (x2 +

10x + 2x + 20) = (x + 1)[x(x + 10) + 2(x + 10)] = (x + 1) (x +2) (x + 10)

Step-by-step explanation:

Let p(x) = x3+13x2+32x+20

Factors of 20 are ±1, ±2, ±4, ±5, ±10 and ±20

By trial method, we find that

p(-1) = 0

So, (x+1) is factor of p(x)

Now,

p(x)= x3 + 13x2 + 32x + 20

p(-1) = (-1)3 + 13(-1)2 + 32(-1) + 20

p(-1) = −1 + 13 – 32 + 20

p(-1) = 0

Therefore, (x+1) is the factor of p(x).

(x + 1)(x2 + 12x + 20) = (x + 1)(x2 + 2x + 10x + 20)

= (x +1)x(x + 2) + 10(x + 2)

= (x +1)(x + 2)(x + 10)

Thus answer is (x +1)(x + 2)(x + 10)