factorise (x³+13x²+31x+20)
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x3 + 13x2 + 32x + 20 = (x + 1)(x2 + 12x + 20) = (x + 1) (x2 + 10x + 2x + 20) = (x + 1)[x(x + 10) + 2(x + 10)] = (x + 1) (x +2) (x + 10
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Answer:
x3 + 13x2 + 32x + 20 = (x + 1)(x2 + 12x + 20) = (x + 1) (x2 + 10x + 2x + 20) = (x + 1)[x(x + 10) + 2(x + 10)] = (x + 1) (x +2) (x + 10
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