Question

factorise x³+13x²+32x+20​

Answer 1

Here ,

${x}^{3} + 13 {x}^{2} + 32x + 20 \\ \\ now \: we \: simplyfy \: above \: equation \: we \: get \\ \\ = {x}^{3} + {x}^{2} + 12 {x}^{2} + 12x + 20x + 20 \\ = {x}^{2} (x + 1) + 12x(x + 1) + 20(x + 1) \\ \\ now \: common \: is \: (x + 1)\: so \: we \: get \: \\ = (x + 1)( {x}^{2} + 12x + 20) \\ = (x + 1)( {x}^{2} + 2x + 10x + 20) \\ = (x + 1) [x(x + 2) + 10(x + 2)] \\ = (x + 1)[(x + 2)(x + 10)] \\ \\ = (x + 1)(x + 2)(x + 10)$

so the factors of given equation is

(x + 1)(x + 2)(x + 10)

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Answer 2

Explanation:

A pole star or polar star is a star, preferably bright, closely aligned to the axis of rotation of an astronomical object. ... A couple thousand years ago, Kochab and Pherkad were twin northern pole stars, though neither was as close to the pole as Polaris is now.