factorise x³+13x²+32x+20
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Answer:
let p(x) = -2
substituting the value we get
(-2)³ + 13×(-2)² + 32×(-2) + 20
-8 + 52 -64 + 20
-72 +72=0
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therefore the factor is x+2
dividing the equation by x+2 we get
x² + 11x + 10
then by simply factorisation.
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we get the factors
(x+2) , (x+1) , (x+10)
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