Question

factorise:- x³+13x²+32x-20​

Answer 1

Answer:

x³+13x²+32x+20:

=(x+1)(x²+12x+20)   [∵, for x=-1, x³+13x²+32x+20=-1+13-32+20=0]

=(x+1)(x²+10x+2x+20)

=(x+1){x(x+10)+2(x+10)}

=(x+1){(x+10)(x+2)}

=(x+1)(x+2)(x+10)

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