factorise x3+13x2+32x+20
Answers
Answered by
0
Answer:
How to solve your problem
3
+
1
3
2
+
3
2
+
2
0
x^{3}+13x^{2}+32x+20
x3+13x2+32x+20
Grouping
1
Find one factor
Factor by grouping
Factor by grouping
Factor by grouping
Factor by grouping
(
+
1
)
(
2
+
1
2
+
2
0
)
{\color{#c92786}{({\color{#c92786}{x+1}})({\color{#c92786}{x^{2}+12x+20}})}}
(x+1)(x2+12x+20)
2
Find one factor
Solution
(
+
1
)
(
+
2
)
(
+
1
0
)
(x+1)(x+2)(x+10)
(x+1)(x+2)(x+10)
= (x + 1) (x +2) (x + 10) Hence, x3 + 13x2 + 32x + 20 = (x + 1) (x +2) (x + 10).
Answered by
2
hi dear
your answer is
The value of x3+13x2+32x+20 is
x3+x2+12x2+12x+20x+20
=x2(x+1)+12x(x+1)+20(x+1)
=(x−1)(x2+12x+20)
=(x−1)(x2+10x+2x+20)
=(x+1)[x(x+10)+2(x+10)]
=(x+1)(x+2)(x+10)
hopes its helps you
Similar questions