Factorise x³+13x²+32x+20
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Answered by
39
x^3+13x^2+32x+20= x^3 + x^2+ 12x^2 + 12x + 20x + 20
=x^2(x+1) + 12x(x+1) +20(x+1)
=(x^2 + 12x + 20)(x+1)
=(x^2 + 10x + 2x + 20)(x + 1)
={x(x + 10) + 2(x + 10)}(x + 1)
=(x+1)(x+2)(x+10)
=x^2(x+1) + 12x(x+1) +20(x+1)
=(x^2 + 12x + 20)(x+1)
=(x^2 + 10x + 2x + 20)(x + 1)
={x(x + 10) + 2(x + 10)}(x + 1)
=(x+1)(x+2)(x+10)
Answered by
10
x^3+13x^2+32x+20= x^3 + x^2+ 12x^2 + 12x + 20x + 20
=x^2(x+1) + 12x(x+1) +20(x+1)
=(x^2 + 12x + 20)(x+1)
=(x^2 + 10x + 2x + 20)(x + 1)
={x(x + 10) + 2(x + 10)}(x + 1)
=(x+1)(x+2)(x+10)
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