factorise x3+13x2+3x+20
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Step-by-step explanation:
let p(x)= x3 + 13x2+32x+20
p(-1)=-1+13-32+20=-33+33=0
on dividing p(x) by( x+1) we get,
p(x) ( x+1)= x2 +12x+20
thus, x3+13x2+32x+20=(x+1) (x2+12x+20)
(x+1) ( x2+10x +2x+20)
( x+1) (x2+10x+2x+20)
(x+1) [x(x+10)+2(x+10)]
(x+1) (x +2) (x+10)
hence,x3+13x2+32x+20=(x+1)(x+2)(x+10
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