Math, asked by mahankalisanthosh35, 5 hours ago

Factorise :X3 -2√2y3+3√3z3+3√6xyz

Answers

Answered by basantpradhan731
0

Answer:

9xy6z is your answer bro

Answered by amitnrw
1

Given :  x³  - 2√2y³  + 3√3z³  + 3√6 xyz

To Find : Factorize

Solution:

x³  - 2√2y³  + 3√3z³  + 3√6 xyz

= x³  + ( -√2 y)³  + (√3 z)³   - 3 x(-√2 y) (√3z)

x = a

-√2 y = b

√3z = c

a³  + b³ + c³  - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ac)

= ( x - √2y  + √3z) ( x²  + 2y²  + 3z²  + √2xy  + √6yz - √3xz)

x³  - 2√2y³  + 3√3z³  + 3√6 xyz =

( x - √2y  + √3z) ( x²  + 2y²  + 3z²  + √2xy  + √6yz - √3xz)

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