Question

Factorise : x3+216y3+8z3-36xyz

Answer 1

Answer:

x³+(6y)³+(2z)³-3×6×2xyz

a³+b³+c³-3abc=(a²+b²+c²-ab-bc-ca)(a+b+c)

so,

x³+(6y)³+(2z)³-3×6×2xyz=(x²+36y²+4z²-6xy-12yz-2xz)(x+6y+2z)