Factorise x3 =23024142x-120
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Answered by
13
Answer:
let P(x) = x^3 - 23x^2 + 142x - 120
checking p(x) = 0
x^3 - 23x^2 + 142x - 120
= 0^3 - 23(0)^3 + 142(0) - 120
= 0 - 0 + 0 - 120
= - 120
here is not 0
x^3 - 23(x)^2 + 142x - 120
= (1)^3 - 23(1)^2 + 142(1) - 120
= 1 - 23 + 142 - 120
= 143 - 143
= 0
here is 0
so, at x = 1 , p(x) = 0
Hence x-1 is a factor of p(x)
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Answered by
6
let P(x) = x^3 - 23x^2 + 142x - 120
checking p(x) = 0
x^3 - 23x^2 + 142x - 120
= 0^3 - 23(0)^3 + 142(0) - 120
= 0 - 0 + 0 - 120
= - 120
here is not 0
x^3 - 23(x)^2 + 142x - 120
= (1)^3 - 23(1)^2 + 142(1) - 120
= 1 - 23 + 142 - 120
= 143 - 143
= 0
here is 0
so, at x = 1 , p(x) = 0
therefore, x-1 is a factor of p(x)
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