Math, asked by motwanidheeraj20, 11 months ago

Factorise x³ - 23x² + 142x - 120​

Answers

Answered by BrainlyRonaldo
5

Answer:

Alternate forms:

(x - 1) (x - 10) (x - 12)

x ((x - 23) x + 142) - 120

(x - 23/3)^3 - 103/3 (x - 23/3) + 1820/27

Simplification:

(x-1)(x^2-22x+120)

(x-1)(x^2-12x-10x+120)

(x-1)[(x^2-12x)-(10x-120)]

(x-1)[x(x-12)-10(x-12)

(x-1)(x-10)(x-12)

Roots:

x=1, 10, 12

Answered by trunghl0509
3

Answer: x^3-x^2-22x^2+22x+120x+120

x^2(x-1)-22x(x-1)+120(x-1)

(x-1)(x^2-22x+120)

(x-1)(x^2-12x-10x+120)

(x-1)[(x^2-12x)-(10x-120)]

(x-1)[x(x-12)-10(x-12)

(x-1)(x-10)(x-12)

Done.Have A Good day

Step-by-step explanation:

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