Question

Factorise: x³ - 23x² + 142x - 120 OR Represent √9.3 on number line.​

Answer 1

Step-by-step explanation:

1) Draw a line segment AB of length 9.3 units.

2) Extend the line by 1 unit more such that BC=1 unit .

3) Find the midpoint of AC.

4) Draw a line BD perpendicular to AB and let it intersect the semicircle at point D.

5) Draw an arc DE such that BE=BD.

Therefore, BE=

9.3

units

Answer 2

Answer:

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$x^{3} -23x^{2} +142x-120\\x^{3} -x^{2} -22x^{2}+22x=120x-120\\]x^{2} (x-1)-22x(x-1)=120(x-1)\\x^{2} (x-1)(x^{2} -22x+120)\\(x-1)(x^{2} -22x+120)\\(x-1)[x^{2} -10x-12x=120]\\(x-1)[x(x-10)-12(x-10)}\\(x-1)(x-10)(x-12)$

hope it helps

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Step-by-step explanation: