Question

factorise x³+27 using identity (x-y)(x²+xy+y²)​

Answer 1

x^3+27

=x^3 + 3^3

=(x+3){x^2-x.3 +3^2)

= (x+3)(x^2-3x+9)

Answer 2

question:

factorise x³+27 using identity (x-y)(x²+xy+y²)

solution:

x=x³

y=27

so,

$(x³-27)(x³+x³+x³(27)+27²)$

$(x³-27)(x^{9} (27)+27²)$

$(x³-27)(x^{9} (27)+729)$

$(x³)(x^{9} (27)+729 - 27)$

$= (x³)(x^{9} (27)+702)$