Question

Factorise x³ + 27y³ ​

Answer 1

Answer:

Step-by-step explanation:

use the formula:  A³ + B³  =  (A + B)(A² - AB + B²)

In  x³ + 27y³  --->  x³ + (3y)³  --->   In the formula, replace A with x and replace B with 3y:

    --->   (x + 3y)(x² - x·3y + (3y)²)

    --->   (x + 3y)(x² - 3xy + 9y²)

Answer 2

Given:

Factories x³ + 27y³ ​

This question is solved with the help of formula

$A^{3}+B^{3}=(A+B)\left(A^{2}-A B+B^{2}\right)$

$x^{3}+27 y^{3}$

we can write it as

$x^{3}+(3 y)^{3}$

$\text { In the formula, replace A with } x \text { and replace } B \text { with } 3 y \text { : }$

$\begin{array}{l}(x+3 y)\left(x^{2}-x \cdot 3 y+(3 y)^{2}\right) \\(x+3 y)\left(x^{2}-3 x y+9 y^{2}\right)\end{array}$

hence the answer is $(x+3 y)\left(x^{2}-3 x y+9 y^{2}\right)\end{array}$