factorise x3-2x2-5x+6
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Step-by-step explanation:
Given :-
x^3-2x^2-5x+6
To find:-
Factorise x^3-2x^2-5x+6?
Solution:-
Given expression is x^3-2x^2-5x+6
It can be written as
x^3-3x^2+x^2-3x-2x+6
It can be arranged as
=> (x^3-3x^2)+(x^2-3x)-(2x-6)
=> x^2(x-3) +x(x-3) -2(x-3)
=> (x-3)(x^2+x-2)
=> (x-3)(x^2-x+2x-2)
=>(x-3)[x(x-1)+2(x-1)]
=> (x-3)(x-1)(x+2)
x^3-2x^2-5x+6 = (x-3)(x-1)(x+2)
Answer:-
Factorization of the given expression x^3-2x^2-5x+6 is (x-3)(x-1)(x+2)
Check:-
(x-3)(x-1)(x+2)
=> [(x-3)(x-1)](x+2)
=> (x^2-x-3x+3)(x+2)
=>(x^2-4x+3)(x+2)
=>x^3-4x^2+3x+2x^2-8x+6
=>x^3-2x^2-5x+6
Verified the given relation.
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