Factorise x³-2x²-x+2
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27
Heya ☺
x^3 - 2x^2 - x + 2
= (x^3 - x) - (2x^2 + 2)
= x(x^2 - 1) - 2(x^2 - 1)
= (x^2 - 1) (x - 2)
= (x^2 - 1^2) (x - 2)
= (x + 1) (x - 1) (x - 2)
Thanks
x^3 - 2x^2 - x + 2
= (x^3 - x) - (2x^2 + 2)
= x(x^2 - 1) - 2(x^2 - 1)
= (x^2 - 1) (x - 2)
= (x^2 - 1^2) (x - 2)
= (x + 1) (x - 1) (x - 2)
Thanks
Answered by
2
X^3-2x^2-x+2= (x^3-x)-(2x^2+2) x(x^2-1)-2(x^2-1)
(x^2-1)(x-2)
(x^2-1^2)(x-2)
(x+1)(x-1)(x-2)
(x^2-1)(x-2)
(x^2-1^2)(x-2)
(x+1)(x-1)(x-2)
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