Question

factorise: x³-2x²-x+2
plz solve by the language and by correct method ​

Answer 1

Answer:

$x {}^{3} - 2x {}^{2} - x + 2 \\ = x {}^{3} + x {}^{2} - 3x {}^{2} - 3x + 2x + 2 \\ = x {}^{2} (x + 1) - 3x(x + 1) + 2(x + 1) \\ = (x {}^{2} - 3x + 2)(x + 1) \\ = (x {}^{2} - 2x - x + 2)(x + 1) \\ = (x(x - 2) - 1(x - 2))(x + 1) \\ = (x - 1)(x - 2)(x + 1)$

Answer 2

Answer:

we can use tha FDS method which means factorise.division.splitting.

Step-by-step explanation:

first we have to factorise it like

put x as 1

(1)^3-2(1)^2-(1)+2

1-2-1+2=0. if it comes 0 then

so ,it means we can proceed to new step called long division.we write as x =1 , it becomes x-1

x^3-2x^2-x+2 /x-1 = x^2-1x+2

if the answer is 0 it means you are going right then we will proceed to our next step that is middle term splitting .. do the middle term splitting of the term x^2-1x+2=(x+1) (x-2) (x-1)