Question

Factorise x³ - 2x²y + 3xy²- 6y³.​

Answer 1

Answer:

Given : x³ - 2x²y + 3xy² - 6y³

Here x² is a common factor in first two terms and 3y² is a common factor in last two terms :  

= x²(x - 2y) + 3y²(x - 2y)

Here (x – 2y) is a common factor :  

= (x - 2y)(x² + 3y²)

Hence, the factorization of x³- 2x²y + 3xy² - 6y³ is (x - 2y)(x² + 3y²).