Factorise: x3+2xy2-4y3+2x2y
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Hey mate,
Given x3 -2x2y + 3xy2– y3, 2x3– 5xy2 + 3x2y – 4y3
Collecting positive and negative like terms together,
we get = x3 +2x3 – 2x2y + 3x2y + 3xy2 – 5xy2 – y3– 4y3
= 3x3 + x2y – 2xy2 – 5y3
Hope it helps.
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