Question

factorise:
x³-3x²-10x+24

Answer 1

Answer:

see the image

Step-by-step explanation:

hope it helps you....

Answer 2

Answer:

Step-by-step explanation:

The polyomial p(x)=x³-3x²-10x+24

= x³+(-2x²-x²)+(2x-12x)+24

=(x³-2x²)+(-x²+2x)+(-12x+24)

=x²(x-2)-x(x-2)-12(x-2)

=(x-2)(x²-x-12)

=(x-2)(x²-4x+3x-12)

=(x-2)[x(x-4)+3(x-4)]

=(x-2)[(x-4)(x+3)]

=(x-2)(x-4)(x+3)

Therefore, Factors of x³-3x²-10x+24

= (x-2)(x-4)(x+3)