Question

factorise x³-3x²+3x+7​

Answer 1

Hey mate here is your answer ➡

${x}^{3} - 3 {x}^{2} + 3x + 7$

${x}^{3} + {x}^{2} - 4 {x}^{2} - 4x + 7x + 7$

${x}^{2} (x + 1) + - 4 {x}^{2} (x + 1) + 7(x + 1)$

$(x + 1)( {x}^{2} - 4x + 7)$

Answer is above .

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Answer 2

⭐Solution ⭐

✏given here

x³-3x²+3x+7

= x³+x²-4x²-4x+7x+7

= x²(x+1)-4x(x+1)+7(x+1)

= (x+1)(x²-4x+7)

= (x+1)[ x = { 4±√(-4)²-4×7)}/2]

=(x+1)[ x= { 4±√(16-28)}/2]

=(x+1)[ x = {4±√-12}/2]

= (x+1)[ x = {4±√12i}/2]

So, Can we write it ,

= (x+1)[x-(4±√12i)/2]

✏Hopes its help's u

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