factorise x³+3x²+6x+18
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x³ + 3x² + 6x + 18
=> x²( x + 3 ) + 6( x + 3 )
=> ( x + 3 ) ( x² + 6 )
=> x²( x + 3 ) + 6( x + 3 )
=> ( x + 3 ) ( x² + 6 )
yasir497:
Thanks
Answered by
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We can factorize it by factor theroem .
First see the value of x which make this polynomial value 0.
i.e p(x)=0
so if x= -3
Then p(-3)=0
therefore its factors will be
X=-3
x+3=0
on dividing p(x) by x+3 we get
which is also factor of p(x)
First see the value of x which make this polynomial value 0.
i.e p(x)=0
so if x= -3
Then p(-3)=0
therefore its factors will be
X=-3
x+3=0
on dividing p(x) by x+3 we get
which is also factor of p(x)
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