Question

factorise x3-3x2+7x-5

please answer my question​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$(x - 1)( {x}^{2} - 2x + 5)$

Step-by-step explanation:

It is given that,

${x}^{3} - 3 {x}^{2} + 7x - 5$

It is 3 degree polynomial, so we can apply hit and trial method to find one factor.

Lets put the value x = 1 in the polynomials.

$= {1}^{3} - 3 \times {1}^{2} + 7 \times 1 - 5$

$= 1 - 3 + 7 - 5$

$= 0$

It equals to zero, therefore (x-1) is a factor of this polynomials.

So dividing the given polynomials by (x-1) ,

we get,

${x}^{3} - 3 {x}^{2} + 7x - 5$

$= (x - 1)( {x}^{2} - 2x + 5)$

After observing, we see that

further, it is not factorisable.

Hence, the factorisation is ,

$(x - 1)( {x}^{2} - 2x + 5)$

Note :- Refer to the attachment