Question

factorise:x³-3x²-9x-5
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Answer 1

Answer:

first we have to find a zero of this polynomial

so, x-5 is a zero of this polynomial

now dividing x - 5 and xcube - 3 x square - 9 x minus 5

we get

x^2 + 2x +1 as quotient

now by splitting the middle term we get

(x^2+x) (x+1)

(x+1)x 1(x+1)

answer is (x-5) (x+1) (x+1)

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Answer 2

Answer:

$(x + 1)(x + 1)(x - 5)$

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