Question

factorise =x³_3x²_9x_5​

Answer 1

here is your ans...

x³ - 3x² - 9x - 5

= x³ + x² - 4x² - 4x  - 5x - 5

= x²(x+1) - 4x(x+1) -5(x+1)

= (x+1)(x² - 4x - 5)

= (x+1)(x² - 5x + x - 5)

= (x+1)[x(x-5) + 1(x-5)]

= (x+1)[(x-5)(x+1)]

= (x+1)(x+1)(x-5)

=(x+1)²(x-5)..

hope it will help you

Answer 2

X raise to power 3 e Plus x raise to power 2 - 4 x raise to power 2 minus 4 x minus 5 x -5 execare bracket open X + 1 bracket close -4 x bracket X + 1 (close -5 (X + 1) X + 1 x square - 4 x minus 5 x + 1 x square - 5 x + X - 5 x + 1 x x minus 5 + 1 x minus 5 x + 1 x minus 5 x + 1 X + 1 X + 1 x minus 5