factorise x3-3x2-9x-5
Answers
Answered by
7
Question:
Factorise x³-3x²-9x-5
Answer:
The factors are (x + 1) (x - 5) (x+ 1)
x = -1 , -1 and -5
Step by step explanation:
x³-3x²-9x-5
= x³ + x2 - 4x² - 4x - 5x -5
= x²(x + 1) - 4x ( x + 1) - 5(x + 1)
= (x + 1) (x² - 4x - 5)
= (x + 1) (x - 5x + x - 5)
= (x + 1) (x - 5) (x+ 1)
x + 1 = 0 x - 5 = 0 x + 1 = 0
x = -1 x = -5 x = -1
Conclusion:
I hope u understood.
Answered by
0
Step-by-step explanation:
=x³-3x²-9x-5
=(x+1) (x²-4x-5)+0
=(x+1) (x²-5x+x-5)
=(x+1) [x (x-5) + 1 (x-5) ]
=(x+1) (x-5) (x+1)
=(x-5) (x+1) (x+1)
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