Question

factorise x3-4x^2-7x+10

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Answer 1

Answer:

x^3-4x^2-7x+10

let x=1

(1)^3-4(1)^2-7(1)+10

1-4-7+10=0

so, (x-1) is a factor.

now divide x^3-4x^2-7x-10 from (x-1)=x^2-3x-10

then by spliting the middle term

x^2-3x-10

x^2-5x+2x-10

x(x-5)+2(x-5)

(x+2)(x-5)

factors are (x-1) (x+2) (x-5)

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