Question

factorise: x³ - 4x² - 7x - 10​

Answer 1

Answer:

x^3-4x^2-7x+10

let x=1

(1)^3-4(1)^2-7(1)+10

1-4-7+10=0

so, (x-1) is a factor.

now divide x^3-4x^2-7x-10 from (x-1)=x^2-3x-10

then by spliting the middle term

x^2-3x-10

x^2-5x+2x-10

x(x-5)+2(x-5)

(x+2)(x-5)

factors are (x-1) (x+2) (x-5)

Answer 2

Answer:

x^3-4x^2-7x=10 as x^3-4x-7x+10=0

=x= 1 is solution to this question=(x-1) is factor of x^3 - 4x - 7x + 10

Dividing x^3 - 4x - 7x + 10 by (x-1)

=(x-1) (x^2 - 3x - 10)

=(x - 1 ) (x - 5 ) ( x+ 2 )