Question

factorise x3-5x2+24
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Answer 1

Answer:

x3+5x2−2x−24=x3+3x2+2x2−2x−24x3+5x2−2x−24=x3+3x2+2x2−2x−24

=x2(x+3)+2x2−8x+6x−24=x2(x+3)+2x2−8x+6x−24

=x2(x+3)+2x(x−4)+6(x−4)=x2(x+3)+(x−4)(2x+6)=x2(x+3)+2x(x−4)+6(x−4)=x2(x+3)+(x−4)(2x+6)

=x2(x+3)+2(x−4)(x+3)=(x+3)(x2+2(x−4))=(x+3)(x2+2x−8)=x2(x+3)+2(x−4)(x+3)=(x+3)(x2+2(x−4))=(x+3)(x2+2x−8)

=(x+3)(x2+4x−2x−8)=(x+3)[x(x+4)−2(x+4)]=(x+3)(x2+4x−2x−8)=(x+3)[x(x+4)−2(x+4)]

=(x+3)(x+4)(x−2)=(x+3)(x+4)(x−2)