Question

factorise -
x³ - 64x​

Answer 1

$x {}^{3} + 0x {}^{2} - 64x + 0$

$x {}^{3} - 8x {}^{2} + 8x {}^{2} + 64x + 0$

Answer 2

SOLUTION

$= > {x}^{3} - 64 \\ \\ = > x( {x}^{2} - 8{}^{2} ) \\ \\ = >x(x + 8) \: (x - 8) \: \: \: \: \: ( {a}^{2} + {b}^{2} )$

hope it helps ☺️