Question

factorise x³ + 64y³​

Answer 1

Answer:

formula (a+b)³= a³+b³+3ab (a+b)

so (x³+64y³)

=x³+ 64y³+3×x×64y (x+64y)

=x³+64y³+ 192xy (x+64y)

=x³+64y³+192x²y+ 12288xy²

Step-by-step explanation:

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Answer 2

The algebraic formula is an equation written for unknown variables. This equation contains both mathematical and algebraic symbols. Some common algebraic symbols are brackets, parentheses, variable, equal, approximately equal, proportional to, delta, sigma, etc. The algebraic formula for $a^3+b^3$ is, $a^3+b^3=(a+b)(a^2-ab+b^2)$

Given: $x^3+64y^3$

Separate these values,$x^3+(4y)^3$

Next, apply these values in the formula, where a to be x and b to be 4y.

Hence,

$x^3+(4y)^3=(x+4y)(x^2-x(4y)+(4y)^2)\\x^3+(4y)^3=(x+4y)(x^2-4xy+16y^2)$

Therefore, the factorization of  $x^3+64y^3$  is $(x+4y)(x^2-4xy+16y^2)$