Question

factorise: x³+6x+11x+6​

Answer 1

Combine like terms

x3+6x+11x+6

x3+17x+6

Solution

x3+17x+6

Answer 2

Answer:

(x+1)(x+2)(x+3)

Step-by-step explanation:

whenever a cubic is given the first root is found from trial and error method we check for +1,-1,+2,-2,+3,-3,+1/2,-1/2,+1/3,-1/3

so checking for +1 we get 1+6+11+6 which is not 0

so +1 is not a root

checking for -1 we get

-1+6-11+6=0

so (-1) is a root

now dividing x^3+6x^2+11x+6 by (x+1)

we get x^2+5x+6

now the roots of the quadratic x^2+5x+6 can be found by the general root formula for a quadratic which is x={-b+/-√(b^2-4ac)}/2a

for the quadratic ax^2+bx+c=0

doing the same for x^2+5x+6 we get (x+2)(x+3) or -2 and -3 as the roots

so the cubic x^3+6x^2+11x+6 when factorised gives (x+1)(x+2)(x+3)

there is a simpler way which is using the synthetic division method

where the process remains the same but dividing a linear by any polynomial becomes easy and the quotient can also be found easily

if you know that method you can sure use it

if you don't please ket me know

I'll explain

I hope this explanation has helped

please mark it the brainliest if you find it useful

have a good day