Question

factorise x³-6x²+11-6​

Answer 1

Mistake in question:

Correct question

Factorize $\large x^3-6x^2+11x-6$

Answer:

( x - 1 ) ( x - 2 ) ( x - 3 )

Step-by-step explanation:

Given :

$\large p(x)=x^3-6x^2+11x-6$

By hit and trial method put x = 1

$\large p(1)=1^3-6\times1^2+11\times1-6\\\\\\\large p(1)=12-12\\\\\\\large p(1)=0$

Now putting x = 2

$\large p(2)=2^3-6\times2^2+11\times2-6\\\\\\\large p(2)=8-24+22-6\\\\\\\large p(2)=30-30\\\\\\\large p(2)=0$

Now putting x = 3

$\large p(3)=3^3-6\times3^2+11\times3-6\\\\\\\large p(3)=27-54+33-6\\\\\\\large p(3)=60-60\\\\\\\large p(3)=0$

So ( x - 1 ) ( x - 2 ) ( x - 3 ) are factors of  p ( x )

Thus we get answer.

Answer 2

Answer:

Hey mate plzz refer to the attachment