factorise x3+6x2+11x+6
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☘ Here it is.....
☘ By hit and trial,
we firstly try put (x+1), so that we can check whether it is a factor of people(x) or not.
☘ Zeroes of (x+1). -
x+1=0
x= -1
☘ Now putting this value to e. q-
= (-1) +6(-1) ^2+11(-1) +6
= -1+6-11+6=0
Hence, it is its factor.
Now, (x+1) ÷ p(x)
Hence, When we divide the given, we get x^2+5x+6 as Sol.
Now we need to factorise it,
= x^2+5x+6
= x^2+3x+2x+6
= x(x+3) +2(x+3)
= (x+2) (x+3)
So, the Sol. are (x+1) (x+2) (x+3).
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