factorise (x³+8) factorise
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hello here is your answer by Sujeet yaduvanshi ✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌ ✌✌✌✌✌✌✌✌✌✌
We know that formula,
a³+b³
then,
arrange in this form,
x³+2³
then,
following the formula,
a³+b³=(a+b)(a²-ab+b²)
then,
a=x
b=2
Now,
x²+2³=(x+2)(x²-2x+4)
that's all
dear friend
by Sujeet
We know that formula,
a³+b³
then,
arrange in this form,
x³+2³
then,
following the formula,
a³+b³=(a+b)(a²-ab+b²)
then,
a=x
b=2
Now,
x²+2³=(x+2)(x²-2x+4)
that's all
dear friend
by Sujeet
Answered by
2
let x3+8=0 then x3=8
x*x*x=2*2*2
therefore x=2
you can also follow (a+b)3
x*x*x=2*2*2
therefore x=2
you can also follow (a+b)3
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