Question

factorise x3-x2-1+x​

Answer 1

Answer:

good night

Step-by-step explanation:

sweet dreams

Answer 2

First, group the two terms on the left and the two terms on the right as:

First, group the two terms on the left and the two terms on the right as:(x3+x2)+(x+1)

First, group the two terms on the left and the two terms on the right as:(x3+x2)+(x+1)Now, factor out an x2 from the term on the left to give

First, group the two terms on the left and the two terms on the right as:(x3+x2)+(x+1)Now, factor out an x2 from the term on the left to give((x2×x)+(x2×1))+(x+1)

First, group the two terms on the left and the two terms on the right as:(x3+x2)+(x+1)Now, factor out an x2 from the term on the left to give((x2×x)+(x2×1))+(x+1)x2(x+1)+(x+1)

First, group the two terms on the left and the two terms on the right as:(x3+x2)+(x+1)Now, factor out an x2 from the term on the left to give((x2×x)+(x2×1))+(x+1)x2(x+1)+(x+1)(x+1) can also be written as 1(x+1) giving:

First, group the two terms on the left and the two terms on the right as:(x3+x2)+(x+1)Now, factor out an x2 from the term on the left to give((x2×x)+(x2×1))+(x+1)x2(x+1)+(x+1)(x+1) can also be written as 1(x+1) giving:x2(x+1)+1(x+1)

First, group the two terms on the left and the two terms on the right as:(x3+x2)+(x+1)Now, factor out an x2 from the term on the left to give((x2×x)+(x2×1))+(x+1)x2(x+1)+(x+1)(x+1) can also be written as 1(x+1) giving:x2(x+1)+1(x+1)We can now factor out an (x+1) from each term giving:

First, group the two terms on the left and the two terms on the right as:(x3+x2)+(x+1)Now, factor out an x2 from the term on the left to give((x2×x)+(x2×1))+(x+1)x2(x+1)+(x+1)(x+1) can also be written as 1(x+1) giving:x2(x+1)+1(x+1)We can now factor out an (x+1) from each term giving:(x+1)(x2+1)