Question

factorise x3-x2-x+1....Plz fast

Answer 1

${\huge {\underline {\underline {\sf {Answer}}}}}$

${\underline {\underline {\rm{Given:}}}}$

• ${x}^{3}-{x}^{2}-x+1$

${\underline {\underline {\rm{Find:}}}}$

Here, we have to factorise the given equation

• Taking out ${x}^{2}$

$\implies$ ${x}^{2}(x-1)-(x-1)$

• Taking out (x-1) from the expression

$\implies$ $(x-1)({x}^{2}-1)$

• Using the identity, ${a}^{2}-{b}^{2}$

$\implies$ $(x-1)({x}^{2}-{1}^{2})$

• As we know, ${a}^{2}-{b}^{2}$ = (a-b)(a+b)

$\implies$ (x-1)(x-1)(x+1)

• Write the repeated multiple in exponential form

$\implies$ $(x-1)^{2}(x+1)$

Hence, $(</u></strong><strong><u>x-1</u></strong><strong><u>)</u></strong><strong><u>^{2}</u></strong><strong><u>(</u></strong><strong><u>x+1)$ is our answer .

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Answer 2

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