factorise x³+y³+64-12xy
wgmvarsha:
pls ans me
Answers
Answered by
34
x³+y³+64-12xy
= x³+y³+4³-3.x.y.4
=(x+y+4)(x²+y²+z³-xy-4y-4x)
= x³+y³+4³-3.x.y.4
=(x+y+4)(x²+y²+z³-xy-4y-4x)
that is not z³ 16
yes
Answered by
17
Step-by-step explanation:
x³+y³+64-12xy
x³+y³+(4)³-12xy
:.x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)
(x+y+4)(x²+y²+4²-xy-4y-4a)
(x+y+4)(x²+y²+16-xy-4y-4a)
I HOPE IT WILL HELP YOU
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