Question

factorise: x³y³-9x²y²+20xy​

Answer 1

Step-by-step explanation:

$\huge \red{\tt \pmb{Factorisation:}}$

x³y³- 9x²y²+20xy

= xy( x²y² - 9 xy + 20 )

= xy( x²y² - 5xy - 4xy + 20 )

= xy{ xy( xy - 5 ) - 4( xy - 5 ) }

= xy{ ( xy - 5) ( xy - 4) }

= xy( xy - 5 ) ( xy - 4 )

Answer 2

Step-by-step explanation:

9x³y+41x²y²+20xy³

xy(9x²+41xy+y²)

xy(9x²+36xy+5xy+20y²)

xy[9x(x+4y)+5y(x+4y)]

xy(x+4y)(9x+5y)