Factorise:x⁴+5x²+9 Thank you
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Answered by
88
Given, x⁴ + 5x² + 9 to factorise
= x⁴ + 6x² + 9 - x²
= [(x²)² + 2×3×(x²) + 3²] - (x)²
= (x² + 3)² - x²
It is in the form of a²-b² which can be written as (a+b)(a-b)
= (x²+3-x)(x²+3+x)
∴ x⁴+5x²+9 = (x²+3-x)(x²+3+x)
= x⁴ + 6x² + 9 - x²
= [(x²)² + 2×3×(x²) + 3²] - (x)²
= (x² + 3)² - x²
It is in the form of a²-b² which can be written as (a+b)(a-b)
= (x²+3-x)(x²+3+x)
∴ x⁴+5x²+9 = (x²+3-x)(x²+3+x)
Answered by
41
[x^4 + 5x²+9]
adding and subtracting x²,
=[x^4 +5x² +x² +9] -x²
=(x^4 +6x² +9) - x²
=(x²+3)² - x²
=(x²+3 +x)(x²+3 -x)
adding and subtracting x²,
=[x^4 +5x² +x² +9] -x²
=(x^4 +6x² +9) - x²
=(x²+3)² - x²
=(x²+3 +x)(x²+3 -x)
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